For the reaction,Hg2++2Cl−⇌HgCl2,K=1.65×1013concentration of Hg2+, at the equivalence point in the titration of 2.0 mmol of Hg2+ with CI- when final volume is 100 mL, is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
8.25×1014M
b
1.65×1013M
c
2.87×106M
d
6.72×10−6M
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Hg2+=2.0 millimoles in 100mL solution =2×10−3mol0.1L =2×10−2M=0.02MSince, stability constant of HgCl2 is large (1 .65x1013), the value of [Hg2+] should be small.At the end point, Cl−=2Hg2+HgCl2=0.020−Hg2+≈0.02M ∴ HgCl2Hg2+Cl−2=1.65×1013 0.02Hg2+2Hg2+2=1.65×1013 ∴ 4Hg2+3=0.021.65×1013 ∴ Hg3+=6.172×106M