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Q.

In the reaction I2+2OH⊖⟶I⊖+IO⊖+H2O . I2  undergoes

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a

Oxidation

b

Reduction

c

Oxidation and reduction

d

complex formation

answer is C.

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Detailed Solution

I20+2OH-→             I⊝+I+1O⊝+H2O iodine oxidation state is changing from 0 to +1 and -1
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