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For the reaction at 273 K, NO(g)+O3( g)⟶NO2( g)+O2( g)It is observed that the pressure of NO(g) falls from 700 mm Hg to 500 mm Hg in 250 s. Calculate the average rate of reaction in a × 10-3 atm s-1. The value of a is

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answer is 1.053.

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Detailed Solution

NO(g)+O3( g)⟶NO2( g)+O2( g) Average rate = Change of pressure Change of time =ΔPΔt=700-500250=200250=200760×250atms-1=1.053×10-3 atm s-1

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