In a reaction, 3 mol of electrons are gained by 1 mol of HNO3. Assuming no change in O.N. of hydrogen and oxygen, the possible product obtained due to reduction will be
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a
1 mol of NO2
b
0.5 mol of N2O
c
1 mol of NO
d
0.5 mol of N2O3
answer is C.
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Detailed Solution
O.N. of N in the product - + 5 -3 = + 2Hence product is NO.