For a reaction N2 + 3H2 → 2NH3, the rate of formation of ammonia was found to be 2.0 × 10-4 mol dm-3 s-1. The rate of consumption of H2 will be

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1.0×10−4mol dm−3 s−1

2.0×10−4 mol dm−3 s−1

3.0×10−4 mol dm−3 s−1

4.0×10−4mol dm−3 s−1

answer is C.

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Detailed Solution

We will have −dN2dt=−13dH2dt=12dNH3dt It is given that dNH3dt=2×10−4moldm−3s−1. Hence, −dH2dt=32dNH3dt=3×10−4moldm−3s−1

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