In the reaction 2N2O5→4NO2+O2, initial pressure is 500 atm and rate constant K is 3.38×10−5sec⁡−1. After 10 minutes the final pressure of N2O5 is

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490 atm

250 atm

480 atm

420 atm

answer is A.

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Detailed Solution

p0=500 atmK=2.303tlogp0pt3.38×10−5=2.30310×60log⁡500pt 0.00880=log⁡500pt ⇒pt= 5001.02=490 atm

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