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In the reaction : ${Na}_{2} S_{2} O_{3} + 4 {Cl}_{2} + 5 H_{2} O \overset{}{\to} {Na}_{2} {SO}_{4} + H_{2} {SO}_{4} + 8 HCl,$ the equivalent weight of ${Na}_{2} S_{2} O_{3}$ will be : (M = molecular weight of ${Na}_{2} S_{2} O_{3}$ )

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M/4

M/8

M/1

M/2

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detailed solution

Correct option is B

Na2S2O3+2 → Na2SO4+6the total change in oxidation number = 4× 2=8∴ ENa2S2O3=mol. wt.v.f=M8

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In the reaction : Na2S2O3 + 4Cl2 + 5H2O → Na2SO4+H2SO4+8HCl, the equivalent weight of Na2S2O3 will be : (M = molecular weight of Na2S2O3)

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In the reaction : ${Na}_{2} S_{2} O_{3} + 4 {Cl}_{2} + 5 H_{2} O \overset{}{\to} {Na}_{2} {SO}_{4} + H_{2} {SO}_{4} + 8 HCl,$ the equivalent weight of ${Na}_{2} S_{2} O_{3}$ will be : (M = molecular weight of ${Na}_{2} S_{2} O_{3}$ )