Q.

In the reaction 2Na2S2O3 +  I2→Na2S4O6+2NaI, the equivalent weight of Na2S2O3 (mol. wt. = M) is equal to

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a

M

b

M / 2

c

M / 3

d

M / 4

answer is A.

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Detailed Solution

Na2S2O3+2 +  I2→Na2S4O6+2.5+NaIn=2  ×  0.5=1E=Mn−factor=M1=M
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