Q.
In the reaction 2Na2S2O3 + I2→Na2S4O6+2NaI, the equivalent weight of Na2S2O3 (mol. wt. = M) is equal to
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a
M
b
M / 2
c
M / 3
d
M / 4
answer is A.
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Detailed Solution
Na2S2O3+2 + I2→Na2S4O6+2.5+NaIn=2 × 0.5=1E=Mn−factor=M1=M
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