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For the reaction, 2NO2+12O2 N2O5  the rate of disappearance of NO2 is  10-3mole.lit-1min-1. Rate of appearance of N2O5 will be

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a
8.33×10-6mole.lit-1s-1
b
8.33×10-5mole.lit-1s-1
c
10-3mole.lit-1s-1
d
5×10-4mole.lit-1s-1

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detailed solution

Correct option is A

rate=-12d[NO2]dt=-2d[O2]dt=+d[N2O5]dt given -d[NO2]dt=10-3mole lit-1min-1 1210-3=+d[N2O5]dt +d[N2O5]dt=5×10-4mole lit-1min-1 +d[N2O5]dt=5×10-460mole lit-1s-1 +d[N2O5]dt=8.33×10-6mole lit-1s-1

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