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a
TΔS<ΔH and Both ΔH and ΔS are tue
b
TΔS>ΔH and both ΔH and ΔS are tue
c
TΔS=ΔH and both ΔH and ΔS are +ve
d
TΔS>ΔH and ΔH is +ve and ΔS is −ve
answer is B.
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Detailed Solution
For spontaneous reaction ∆G should be negativeΔG=ΔH−TΔS=(+ve)−T(+ve)If TΔS>ΔH then ∆G will be negative and reaction will be spontaneous at high temperature.