For the reactionPCl5(g)⇔PCl3(g)+Cl2(g) , the value of Kp is 10−2 atm, the pressure at equilibrium is 1 atm, what is the degree of dissociation ofPCl5

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0.1

0.01

answer is B.

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Detailed Solution

Pcl5⇌Pcl3+cl2 kp=10-2 p=1atm α=kpkp+p α=10-210-2+1 =0.011.01=1100≈10-1

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