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Q.

For the reaction PCl3(g) + Cl2(g) ⇌ PCl5(g), the value of KP at 2500C is 0.61 atm-1. The value of KC at this temperature will be

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a

15 mol/l-1

b

26 mol/l-1

c

35 mol/l-1

d

52 mol/l-1

answer is B.

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Detailed Solution

PCl3(g) + Cl2(g) ⇌ PCl5(g),∆n=-1, KP=0.61 atm-1KC=KPRT-∆n= 0.61 (0.0821 x 523)1 = 26 mol/L

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