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Q.

For the reaction,  PCl5(g)⇌PCl3(g)+Cl2(g)  at 121.8K . logKp  - logKc is equal to (R = 0.0821 lit atm K-1 mole-1)

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a

Zero

b

10

c

1

d

0.1

answer is C.

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Detailed Solution

Δng=2−1=1Kp=KcRT1KpKc=0.0821×121.8KpKc=10logKp−logKc=log10logKp−logKc=1
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