The reaction, PCl5  ⇌  PCl3  + Cl2  is started in a 5 litre container by taking one mole of PCl5. If 0.3 mole of PCl5 is there at equilibrium, concentration of PCl3 and KC will respectively be

PCl5      ⇌           PCl3      +        Cl21                              0                      0       Initial mole1 - 0.75               0.75                 0.75  Conc. at equilibriumTotal mole of PCl3 = 0.7Concentration = 0.14KC = x21-xV= 0.7 × 0.70.3 ×5= 49150=0.326