Q.

Reaction of propanamide with ethanolic sodium hydroxide and bromine will give

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a

Aniline

b

Ethylamine

c

Methylamine

d

Propylamine

answer is B.

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Detailed Solution

CH3CH2CONH2Propanamide→Br2NaOH/EthanolCH3CH2NH2Ethylamine
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