For reaction RX+OH−→ROH+X−, rate expression is R=4.7×10−5[RX][OH−]+2.4×10−5[RX].What % of reactant react by SN2 mechanism when [OH−]=0.001 molar?

rSN1=KR-X1 rSN2=KR-X1OH-1 rSN2=4.7×10-5R-X10-3 rSN1=2.4×10-5R-XFraction of reactant Reacted by SN2 mechanism             =4.7×10−5[RX][OH−]4.7×10−5[RX][OH−]+2.4×10−5[RX]            =4.7×10-5×10-3R-X4.7×10-5×10-3R-X+2.4×10-5R-X×100             =  1.9