In the reaction the stoichimetric coefficients of Cr2O72−, NO2− and H+ respectively are : Cr2O72−+NO2−+H+→Cr+3+NO3−+H2O
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a
1,3,8
b
1,4,8
c
1,3,12
d
1,5,12
answer is A.
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Detailed Solution
The balanced stoichiometric chemical equation is Cr2O72−+3NO2−+8H+→2Cr+3+3NO3−+4H2O Hence the stoichiometric coefficients ofCrO72−,NO2− and H+ would be 1,3,8.