The reaction in which $\mathrm{\Delta H}=\mathrm{\Delta E}$ is

$\begin{array}{l}\left(1\right)\mathrm{\Delta n}=2-3=-1;\mathrm{\Delta H}<\mathrm{\Delta E}\\ \left(2\right)\mathrm{\Delta n}=2-1=1;\mathrm{\Delta H}>\mathrm{\Delta E}\\ \left(3\right)\mathrm{\Delta n}=1-1=0;\mathrm{\Delta H}=\mathrm{\Delta E}\\ \left(4\right)\mathrm{\Delta n}=2-1=1;\mathrm{\Delta H}>\mathrm{\Delta E}\end{array}$

Only gaseous moles are to be considered while calculating $∆\mathrm{n}$