The reaction which occur in the Galvanic cell is MnO4−+8H++5Fe2+⟶Mn2++5Fe3++4H2OE∘MnO4−,Mn2+,H+∣Pt=1.51V and E∘Fe3+,Fe2+∣Pt=0.77V(Q). If H3O+=2.0M,Fe3+=2.0M,Fe2+=0.5M Mn2+=0.5M,MnO4−=1.0MCalculate the emf of the cell.

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-0.747 V

+0.747 V

-0.733

+0.736 V

answer is D.

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Detailed Solution

Ecell =0.74V−RT5Fln⁡(0.5)(2.0)5(1.0)(2.0)8(0.5)5 =0.74V−0.0595log⁡1(2.0)3(0.5)4 =0.74V−0.0595log⁡2=0.74V−0.059×0.3015=0.736V

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