The reaction which occur in the Galvanic cell is MnO4−+8H++5Fe2+⟶Mn2++5Fe3++4H2OE∘MnO4−,Mn2+,H+∣Pt=1.51V and E∘Fe3+,Fe2+∣Pt=0.77V(Q). The other concentrations are kept at unity except reducing Mn2+to 0.50 M, the emf of the cell is increased by

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0.012 V

3.55×10−3V

0.059 V

0.018 V

answer is B.

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Detailed Solution

ΔE=−0.0595log⁡(0.5)=+3.55×10−3V

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