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Q.

In the reaction2X+B2H6⟶BH2X2⊕BH4⊝the amine(s) X is (are)

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a

NH3

b

CH3NH2

c

(CH3)2NH

d

(CH3)3N

answer is A.

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Detailed Solution

when X is  NH3    ----       2NH3+B2H6⟶BH2NH32⊕BH4⊖ CH3NH2----      2CH3NH2+B2H6⟶BH2CH3NH22⊕BH4⊖ CH32NH---    2{ CH32NH } +B2H6⟶BH2{ CH32NH }2⊕BH4⊖ where as  with teritiary amine  CH33N with  B2H6 forms an adduct:  2 CH33N+B2H6⟶2 CH33N⟶BH3
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