In the reaction X(g)+Y(g)⇌2Z(g) 2 mole of X, 1 mole of y and 1 mole of Z are placed in a 10 liter vessel and allowed to reach equilibrium. If final concentration of Z is 0.2 M, then Kc for the given reaction is :

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1.60

803

163

None of these

answer is C.

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Detailed Solution

X(g) + Y(g) ⇄ 2Z(g) t=0, 0.2M 0.1M 0.1M teq, (0.2-x) (0.1-x) (0.1+2x) ∵ [Z]=(0.1+2x)=0.2 ⇒ x=0.05 Now, kc=[Z]2[X]1[Y]1=0.2×0.20.15×0.05=163

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