For the reaction, XA +YB → ZC,  if −d[A]dt=−d[B]dt=1.5d[C]dt, then the correct  statement among the following is :

XA+YB→    ZC−1XdAdt =  −1YdBdt = +1ZdCdt Given,  −dAdt =  −dBdt = 1.5dCdt −dAdt =  −dBdt = 32dCdtDividing throughout  by factor three−13dAdt =  −13dBdt = +12dCdtThus the stoichiometric reaction would be 3A+3B→    2CX = Y = 3 ; Z = 2