For the reaction XCO3(s)⇌XO(s)+CO2(g),Kp=1.642 atm at 727∘C. If 4 Mole of XCO3(s) was put into a 50 liter container and heated to 727OC What mole percent of the XCO3, remains unreacted at equilibrium?

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None of these

answer is C.

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Detailed Solution

Moles ofCO2 present at equilibrium =1.642×500.0821×1000=1 ∵Kp=PCO2=nRTV Mole % of XCO3 decomposed =14×100=25%Hence, 75% remains undecomposed

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