The reducing power of a metal depends on various factors. Suggest the factor which makes lithium, the strongest reducing agent in aqueous solution.
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a
Sublimation enthalpy
b
Ionisation enthalphy
c
Hydration ehthalpy
d
Electron gain enthalpy
answer is C.
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Detailed Solution
Reducing property of a metal depends upon various factors1) sublimation enthalpy [IE] 2) Ionisation energy [IE] 3) Hydration enthalpy: [HE] Size of M+ ions : Li+ < Na+ < K+ < Rb+ < Cs+H.E Order : Li+>Na+>K+>Rb+>Cs+As the size of M+ ion ↑, Nuclear charge ↓es and hence attractive forces on the water molecule ↓es, and hence degree of hydration ↓esTherefore hydration energy ↓esi.e Li+ ion has highest hydration energysublimation energy (S.E) & Ionisation energies [IE] are absorbed energies,where as hydration energy [H.E] is released energyIn the case of Li As high H.E of "Li" it can easily gives the electrons in large number, therefore it can acts as strongest reducing agent in aqueous solutions among [alkali] metals in the periodic table.