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Q.

The reduction potential of hydrogen electrode is -118 mV. The concentration of H+ in the solution is

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a

0.01 M

b

2 M

c

10-4M

d

1 M

answer is A.

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Detailed Solution

Ecell=0.0591nlog⁡[H+]−0.118=0.05911log⁡[H+]0.1180.0591=−log⁡[H+]⇒[H+]=0.01 M
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