Q.

Reduction potential of Iron electrode in contact with 0.01M FeSO4 solution is EFe+2/Feo = −0.44V

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answer is 4.

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Detailed Solution

EFe+2/Fe = EFe2+/Feo+ 0.05912logFe+2; EFe+2/Fe =  -0.44 V+ 0.05912log10-2 ; EFe+2/Fe =  -0.50 V;
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