Reduction potential of Silver electrode in contact with 0.1M AgNO3 solution is ( EAg+/Ag0=+0.8M )

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+0.68 V

+0.86 V

+0.92 V

+0.74 V

answer is D.

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Detailed Solution

EAg+/Ag=EAg+/Ag0+0.05911log Ag+ EAg+/Ag=+0.8+0.0591 log10-1 EAg+/Ag=+0.74 V

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