Refer to Ellingham diagram in Q.138. The temperature at which C reduces FeO to give Fe and CO is

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Above temperature at point P.

Above temperature at point P but below temperature at point R.

Below temperature at point P.

Approximately at temperature corresponding to point P.

answer is A.

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Detailed Solution

At point P, ΔfGΘ(C,CO)<ΔfGΘ (Fe, FeO) therefore above point P, carbon reduces FeO to Fe and giving CO. Hence carbon reduces FeO.

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