Regarding the -NH2 group of aniline, correct statement is
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a
It shows +M effect only
b
It shows -I effect only
c
It shows -I, -M effect
d
It shows -I, +M effect
answer is D.
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Detailed Solution
In aniline lone pair is less available for donation due to resonance. Aniline is less basic than ammonia.Due to higher electronegativity of nitrogen as compared to carbon, -NH2 gp shows “-I” effect.Due to the donation of lonepair to benzene ring, -NH2 gp shows “+M” effect .+M effect >>> -I effect, it is highly activating group towards ESR.