The relationship between the dissociation energy and N2 and N2+is

(i) N2 ( 14 electrons) =KK∗,σ2s2,σ2s2,π2px2≈π2py2,σ2pz2 Bond Order =12Nb−Na=12(8−2)=3 (ii) N2+(13 electrons )=KK∗,σ2s2,σ∗2s2,π2px2≈π2py2,σ2pz1 Bond Order =12(7−2)=2.5Since, bond dissociation energy ∝ bond order. Hence, bond dissociation energy of N2 is greater than that of the bond dissociation energy ofN2+.