Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH3)3Cl]Cl in 3 mol H2O is 12. When the given solution reacts with excess of AgNO3 solution the number of moles of AgCl produced is.

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1 mol AgCl

0.25 mol AgCl

2 mol AgCl

0.40 mol AgCl

answer is A.

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Detailed Solution

Let degree of ionisation of the complex, [Cu(NH3)3Cl]Cl be α [Cu(NH3)3Cl]Cl⇌[Cu(NH3)Cl]++Cl−i=1+αΔppo=n1(1+α)n1(1+α)+n2=2(1+α)2(1+α)+3=12α=0.5Total Cl− produced 2α=2×12=1 mole ∴ 1 mole of AgCl is produced.

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