Q.

Relative decrease in vapour pressure of an aqueous solution containing 2 moles [Cu(NH3)3Cl]Cl in 3 mol H2O is 12. When the given solution reacts with excess of AgNO3 solution the number of moles of AgCl produced is.

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

1 mol AgCl

0.25 mol AgCl

2 mol AgCl

0.40 mol AgCl

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Let degree of ionisation of the complex, [Cu(NH3)3Cl]Cl be α [Cu(NH3)3Cl]Cl⇌[Cu(NH3)Cl]++Cl−i=1+αΔppo=n1(1+α)n1(1+α)+n2=2(1+α)2(1+α)+3=12α=0.5Total Cl− produced 2α=2×12=1 mole ∴ 1 mole of AgCl is produced.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET