First slide

Theory of dilute solutions

Question

The relative decrease in VP of an aqueous glucose dilute solution is found to be 0.018. Hence, the elevation in boiling point is X⁰C,the value of X is (it is given 1 molal aqueous urea solution boils at 100. 54 $°$ C at 1 atm pressure)

Moderate

Solution

$X_{B} = \frac{∆ P}{P_{A} °} = 0.018 ∆ T_{b} = K_{b} . m \Rightarrow 0.54 \times 1, K_{b} = 0.54 m = \frac{X_{B}}{1 - X_{B}} \times \frac{1000}{M w_{A}} m = \frac{0.018}{0.982} \times \frac{1000}{18} = 1.0 \Rightarrow ∆ T_{b} = K_{b} \times m = 0.54 ° C$

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