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The relative decrease in VP of an aqueous glucose dilute solution is found to be 0.018. Hence, the elevation in boiling point is X0 C,the value of X is (it is given 1 molal aqueous urea solution boils at 100. 54°C at 1 atm pressure)

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answer is 0000.54.

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Detailed Solution

XB=∆PPA°=0.018 ∆Tb=Kb.m⇒0.54×1, Kb=0.54 m=XB1-XB×1000MwA m=0.0180.982×100018=1.0⇒∆Tb=Kb×m=0.54°C

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The relative decrease in VP of an aqueous glucose dilute solution is found to be 0.018. Hence, the elevation in boiling point is X0 C,the value of X is (it is given 1 molal aqueous urea solution boils at 100. 54°C at 1 atm pressure)