The residue obtained on strongly heating 2.76 g Ag2CO3 isAg2CO3→∆Ag+CO2+O2Atomic mass of Ag = 1008

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

3.2 g

3.0 g

2.0 g

2.16 g

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Ag2CO3→ 2Ag+CO2↑+O2↑(Mw=276g) (2×108g)The residue is due to Ag276g of Ag2CO3 = 2 ×108 g Ag2.76 g of Ag2CO3=2×108×2.76276=2.16 g

Watch 3-min video & get full concept clarity