First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

Resistance of 0.2 M solution of an electrolyte is $50 Ω$ . The specific conductance of the solution is 1.3 Sm^-1.If resistance of the 0.4 M solution of the same electrolyte is $260 Ω$ ,its molar conductivity is

Moderate

A

$6250 S m^{2} {mol}^{- 1}$
B

$6 .25 \times 10^{- 4} S m^{2} {mol}^{- 1}$
C

$625 \times 10^{- 4} S m^{2} {mol}^{- 1}$
D

$62 .5 S m^{2} {mol}^{- 1}$

Solution

Specific conductance = conductance x cell constant
$1 .3 {Sm}^{- 1} = \frac{1}{50} S \times cell constant$
$∴ Cell constant = 1 .3 \times 50 m^{- 1} = 65 m^{- 1} = (65 / 100) {cm}^{- 1}$
$Molar conductivity = \frac{1000 \times conductance \times cell constant}{molarity}$
$\begin{array}{l} = \frac{1000}{0 .4} \times \frac{1}{260} \times \frac{65}{100} = 6 .25 {Scm}^{2} {mol}^{- 1} \\ = 6 .25 \times 10^{- 4} {Sm}^{2} {mol}^{- 1} \end{array}$

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