Q.
The resistance of 0.1 N solution of formic acid is 200 ohm and cell constant is 2.0 cm-1. The equivalent conductivity (in Scm2eq-1) of 0.1 N formic acid is:
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a
100
b
10
c
1
d
none of these
answer is A.
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Detailed Solution
κ=G.G∗⇒12002⇒0.01Λeq=κN×1000⇒0.010.1×1000⇒100
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