The resonance energy of N2O from the following data is _______ΔfH∘ of N2O=82kJmol−1eN≡N=946kJmol−1eN=N=418kJmol−1eO=O=498kJmol−1eN=O=607kJmol−1

Given, N2+12O2→N2O;ΔexpH=82kJAlso, using bond energy data for structure of N2O as N = N = O,  the Δcal H for N2O is given below, ΔcalH=B.E . data of formation +B.E . data of dissociation ΔcalH=−eN=N+eN=0+eN≡N+12×eO=0=−[418+607]+946+12×498=+170kJ∴ Resonance energy =Exp.ΔH− calculated ΔH=82−170=−88kJ