The results given in the below table were obtained during kinetic studies of the following reaction:2A+B→C+DX and Y in the given table are respectively:

If rate law is R=KAaBbFrom expt. I & II:R2R1=KA2aB2bKA1aB1b2.4×10−26×10−3=0.10.1a0.20.1b4=2b⇒b=2          respectively from expt. III & I:R3R1=KA3aB3bKA1aB1b1.2×10−26×10−3=0.20.1a0.10.1b2=2a⇒a=1∴R4R1=x0.10.20.12726=x0.1×4=⇒x=0.3R5R4=0.30.31y0.2228872=y0.22⇒y=0.4