Q.

For reversible operation of the lead storage cell (given in following figure) at 298 K and all species in the cell in their standard state, Select the correct statement(s) based on following data.Half cell reaction E°(volt) PbO2(s)+SO4−2(aq)+4H+(aq)2e−→PbSO4(s)+2H2O(ℓ)+1.7VPbO2(s)+4H++2e−→Pb+2(aq)+2H2O(ℓ) +1.46VPb+2(aq)+2e−→Pb(s) −0.13VPbSO4(s)+2e−→Pb(s)+SO4−2(aq)ΔH∘ of the overall cell reaction =−306kJ/mol

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

Maximum electrical work that can be extracted from the cell during discharge is 386 kJ/ mol approximately for the cell reaction

b

Concentration of H2SO4 decreases during cell discharge

c

During discharging  ∆S for cell reaction is negative

d

Thickness of cathode & anode increases during cell discharge

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Anode : Pbs+SO42−aq→  PbSO4s+2e−E° = 0.3VCathode: PbO2+SO42−aq+4H++2e−→  PbSO4+2H2Ol E° = 1.7 VEcello=2VΔGcetl ∘=−(2)(96500)(2)1000=−386ΔG∘=ΔH∘−TΔS∘TΔS∘=ΔH∘−ΔG∘TΔS∘=−306+386=80ΔS∘=+
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

+91
whats app icon