In the reversible reaction A+B⇌ C + D, the concentration of each C and D at equilibrium was 0.8 mole/litre, then the equilibrium constant KC will be

Suppose 1 mole of A and B is each taken, then 0.8 mole/litre of C and D each formed remaining concentration of A and B will be (1 - 0.8) = 0.2 mole/litre.KC = C DA B = 0.8 × 0.80.2 × 0.2=16