In a reversible reaction Kc > Kp and ∆H= + 40 K.Cal. The product will be obtained in less amount on
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a
Increasing both pressure & temperature
b
Decreasing both pressure & temperature
c
Decreasing pressure & increasing temperature
d
Increasing pressure & decreasing temperature
answer is B.
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Detailed Solution
Given KC > KP. This indicates Δn = negative nP(g) < nR(g)Thus forward reaction is favoured at high pressure (endothermic), High temperature favours forward reaction.Product obtained is less whenTemperature is lowPressure is low