Q.

In a reversible reaction Kc > Kp and ∆H= + 40 K.Cal. The product will be obtained in less amount on

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Increasing both pressure & temperature

Decreasing both pressure & temperature

Decreasing pressure & increasing temperature

Increasing pressure & decreasing temperature

answer is B.

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Detailed Solution

Given KC > KP. This indicates Δn = negative nP(g) < nR(g)Thus forward reaction is favoured at high pressure (endothermic), High temperature favours forward reaction.Product obtained is less whenTemperature is lowPressure is low

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