Q.

In a reversible reaction Kc > Kp and  ∆H= + 40 K.Cal. The product will be obtained in less amount on

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a

Increasing both pressure & temperature

b

Decreasing both pressure & temperature

c

Decreasing pressure & increasing temperature

d

Increasing pressure & decreasing temperature

answer is B.

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Detailed Solution

Given KC > KP. This indicates Δn = negative nP(g) < nR(g)Thus forward reaction is favoured at high pressure (endothermic), High temperature favours forward reaction.Product obtained is less whenTemperature is lowPressure is low
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