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For a reversible reaction A⇌K2K1B the rate constant for forward K1=1015·e-2000Tand backward K2=1012·e-2000Tvalue of ΔG0RT for the given reaction at equilibrium is ___?

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answer is 6.91.

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Detailed Solution

Equilibrium constant =K1K2ΔG0=-RTlnKeqΔG0RT=-ln103=-6.909=-6.91

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