For the reversible reaction,N2(g)+3H2(g)⇌2NH3(g) at 500°C, the value of Kp is 1.44×10-5, when the partial pressure is measured in atmospheres. The corresponding value of KC with concentration in molL-1 is

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1.44×10-5/(0.082×500)-2

1.44×10-5/(8.314×773)-2

1.44×10-5/(0.082×773)2

1.44×10-5/(0.082×773)-2

answer is D.

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Detailed Solution

Δn =2-4=-2T=273+500=773KC=KpRT'Δn=1.44×10-5(0.082×773)-2

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