For the reversible reaction N2+O2⇌2NO activation energy of the forward reaction is greater than that of backward reaction. The slope of In K Vs I/T (abscissa) graph will be:

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Zero

−ΔH2.303R

ΔH2.303R

−ΔHR

answer is D.

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Detailed Solution

In K = Constant −ΔHRT Since, Ea(forward)>Ea(backward),the reaction is Endothermic, ΔH>0, Hence slope=−ΔHR

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