In the reversible reaction 2 NO2⇌N2O4 .The rate of disappearance of NO2 is equal to
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a
2k1k2[NO2]2
b
2k1[NO2]2 − 2k2[N2O4]
c
2k1[NO2]2 −k2[N2O4]
d
(2k1−k2)[NO2]
answer is B.
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Detailed Solution
For the reaction, 2 NO2⇌k2k1N2O4, Given ,The rate of disappearance of NO2 =?For forward reaction rate= −12dNO2dt=dN2O4dt =k1[NO2]2 For backward reactionRate=−dN2O4dt=12dNO2dt=k2[N2O4]. Rate of disappearance of NO2 = (Rate of disappearance of NO2− Rate of appearance of NO2 )=2k1[NO2]2−2k[N2O4].