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a
CH2ClCOOH>HCOOH>C2H5COOH>CH3COOH
b
CH2ClCOOH>HCOOH>CH3COOH>C2H5COOH
c
C2H5COOH>CH3COOH>HCOOH>CH2ClCOOH
d
HCOOH>CH2ClCOOH>CH3COOH>C2H5COOH
answer is B.
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Detailed Solution
Presence of electron withdrawing groups (like halogens, -NO2 , -CN…etc.) stabilizes the carboxylate anion and strengthens the acid.Presence of electron donating group (like -CH3 , -C2H5….etc.) destabilizes the carboxylate anion and weakens the acid.