ROH→HClRCl; the alkyl group -R in this reaction is
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a
-CH(CH3)2
b
-CHCH3
c
-C(CH3)3
d
All of these
answer is C.
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Detailed Solution
1° alcohol and 2° alcohol require anhydrous ZnCl2 along with HCl to form alkyl halides. 3° alcohols convert to 3° alkyl halides even in presence of HCl. No doubt anhydrous ZnCl2 can be used but not required.