ROH→HClRCl; the alkyl group -R in this reaction is

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-CH(CH3)2

-CHCH3

-C(CH3)3

All of these

answer is C.

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Detailed Solution

1° alcohol and 2° alcohol require anhydrous ZnCl2 along with HCl to form alkyl halides. 3° alcohols convert to 3° alkyl halides even in presence of HCl. No doubt anhydrous ZnCl2 can be used but not required.

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