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Q.

%S character of bonding orbital of sulphur in H2S is (bond angle H-S-H=92°, cos 92° = -0.035)

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a

25%

b

3.38%

c

20%

d

33.33%

answer is B.

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Detailed Solution

cos⁡92∘=SS−1−0.035=SS−1⇒−0.035S+0.035=S0.035=S(1.035)S=0.0351.035=0.0338%S =3.38%
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