First slide

2nd Law of Thermodynaimcs

Question

ΔS_sur for H₂+1/2O₂ $\to$ H₂O, ΔH= - 280 KJ at 400 K is

Easy

Solution

$\begin{array}{l} \Delta {S_{Surr.}} = - \Delta {S_{sys}}\\\\ \Delta {S_{Surr.}}\, = - \left( {\frac{{\Delta {H_{sys}}}}{T}} \right) = - \left( {\frac{{ - 280 \times 1000}}{{400}}} \right)\\\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \,700J/mole/K \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App