First slide

Solubility product(KSP)

Question

A salt $M_{2} X_{3}$ dissolves in water such that its solubility is x g. mole/liter. Its $K_{SP}$ is

Moderate

A

$x^{5}$
B

$6 x^{2}$
C

$108 x^{5}$
D

6 $x^{5}$

Solution

Solubility of $M_{2} X_{3} = x g mole / litre$
$M_{2} X_{3} ⇌ 2 M^{+ 3} + 3 X^{- 2}$
$∴ [M^{+ 3}] = 2 x [X^{- 2}] = 3 x$
Solubility product $K_{SP} = {(2 x)}^{2} . {(3 x)}^{3} = 108 x^{5}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App